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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 6 (4362/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 6 (4362/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 6 (4362/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 6 (4362/01)

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Most candidates thought that David was correct in part (a) because you would get a negative value for n in Jodie’s equation. In (b), most candidates could solve David’s equation correctly but made errors with Jodie’s. Some candidates gave the answer of 3.5 for both equations. Very few candidates could correctly explain the error that Jodie had made in part (c) but could give the correct value of n.

Tags

  • Algebra
  • Linear equations

Mathematics (GCSE) - Higher Tier

Winter 2017 | Question 6 (4352/02)

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Mathematics (GCSE) - Higher Tier

Winter 2017 | Question 6 (4352/02)

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Mathematics (GCSE) - Higher Tier

Winter 2017 | Question 6 (4352/02)

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Mathematics (GCSE) - Higher Tier

Winter 2017 | Question 6 (4352/02)

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A good number of fully correct solutions were seen here, though some candidates failed to initially equate the angle sum of the triangle to 180 degrees.

Tags

  • Algebra
  • Linear equations
  • Angles in a polygon
  • Geometry

Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 13 (4352/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 13 (4352/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 13 (4352/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 13 (4352/01)

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Most candidates did not realise that the sum of the three angles in the triangle was 180⁰. So they did not set up the correct equation to solve.

Very many wrote down the following wrong statements:

4x + 9 = 13x, 6x – 12 = - 6x, 8x + 3 = 11x.

After that, they didn’t know how to proceed.

This question was very difficult for most candidates.

Tags

  • Algebra
  • Linear equations
  • Angles in a polygon
  • Geometry

Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 14 (4352/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 14 (4352/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 14 (4352/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 14 (4352/01)

Q

(a) Most candidates were unable to evaluate 52 - 2×5 – 3 correctly.

 

(b) Plotting the points was well done though many were unable to plot the negative y-values correctly. Candidates found the vertical scale difficult to use as two small squares represented 1.

However, there were many good attempts at drawing a proper curve and few polygons were seen.

 

(c) Very many were unable to draw the horizontal line y = 3, either omitting this part or drawing a random straight line.

 

(d) Both the curve and the straight line needed to be drawn to find the points of intersection. As many were unable to draw at least one of these, then they were unable to answer this part of the question.

Tags

  • Algebra
  • Quadratic graphs

Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 12 (4353/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 12 (4353/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 12 (4353/01)

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Mathematics (GCSE) - Foundation Tier

Winter 2017 | Question 12 (4353/01)

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Parts (a) and (b) were well answered. The scale of the horizontal axis (one small square equates to 3 minutes) caused a problem for some candidates in part (c) although one mark could easily be obtained from locating the finishing point of the graph. There was a good response in part (d) and comments about the slope or steepness of the graph were offered as explanations as to why the cyclist had moved “more slowly”.

Tags

  • Algebra
  • Distance-time graphs
  • Travel graphs

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